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ID: 969957 • Letter: L
Question
Explanation / Answer
1) From first law of thermodynamics
Change in internal energy= Q+W
Q and W are +Ve if added to the system
Change in internal energy= 285+115= 400 joules
2) For a constant pressure process
work done = -nR ( T2-T1), n= number of moles of gas
R= 8.314 Joule/mole.K T2=125 deg.c T1= 0 deg.c
Work done = -2.5*8.314*(125-0) =-2538. 125.
Heating at constant pressure leads to expansion of gas and gas does work
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