Need quick chem help The energy difference between the sets of d orbitals is cal

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Need quick chem help

The energy difference between the sets of d orbitals is called the crystal field splitting energy, delta. When delta is large, d electrons are placed in the lower energy d orbitals and are paired (low-spin complex). When delta is small, electrons are placed in both the higher and lower energy orbitals before any pairing occurs (high-spin complex). The complex ion [CoBr_6]^3 is a high-spin complex and absorbs light at a wavelength greater than 7.70 times 10^2 nm. How many unpaired electrons will be present in the complex? Express your answer numerically as an integer. If the Br^1 ligands are substituted with CN^- ligands to form [Co(CN)_6]^-3, the complex becomes low spin and absorbs light at 2.90 times 10^2 nm. How many unpaired electrons are in [Co(CN)_6]^3- ? Express your answer numerically as an integer. The complex ion [Co(CN)_6]^3- absorbs a photon of wavelength 2.90 times10^2 nm. What is the splitting energy, delta, of this complex? Express the splitting energy in kilojoules per mole. Ligands are ordered in terms of their ability to split the d orbitals in the spectrochemical series as follows: I^-

Explanation / Answer

Part A) 4 unpaired electron

Part B) Zero (0) unpaired electron

Part C) 412.9 kJ/mol

Part D) between 2.90*102 nm and 7.70*102 nm

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