At 1,350 K, ?G = 6 . 44 × 10 5 J?/?mol. At 1,375 K, ?G = 1 . 98 × 10 5 J?/?mol.

Question

At 1,350 K, ?G = 6.44 × 105 J?/?mol.

At 1,375 K, ?G = 1.98 × 105 J?/?mol. The reaction would be at equilibrium at about 735 K. The reaction is nonspontaneous at 1,400 K.

At 1,350 K, ?G = 6.44 × 105 J?/?mol.

At 1,375 K, G = 1.98 × 105 J /mol. Which statement about the hydration of sulfur trioxide is NOT correct? SO2 (g)+H2O(g) H2SO4(aq) (AH-227 kJ/mol and dS ~-309 J/mol·K) The reaction would be at equilibrium at about 735 K. The reaction is nonspontaneous at 1,400 K At 1,350 K, G = 6.44 × 105 J/mol.

Explanation / Answer

1) DG = DH-TDS

= (-227*10^3)-(-309*1375)

   = 197875 joule.

2) DG = (-227*10^3)-(-309*735)

      = 115 joule

reaction is not at equilibrium

3) DG = (-227*10^3)-(-309*1400)

    = 205600 joule

DG+ve.so that the reaction is nonspontaneous.

4) = (-227*10^3)-(-309*1350)

   DG = 190150 joule

answer:

at 1350 DG = 6.44*10^5 j/mol

the reaction would be at equilibrium at about 735 k

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