A 25.121 mg sample of a chemical known to contain only carbon, hydrogen, sulfur,

Question

A 25.121 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 44.751 mg of carbon dioxide and 18.319 mg of water. In another experiment, 23.467 mg of the compound is reacted with excess oxygen to produce 10.142 mg of sulfur dioxide. Add subscripts below to correctly identify the empirical formula of this compound (use this order of elements: CHSO).

A 25.121 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis apparatus, yielding 44.751 mg of carbon dioxide and 18.319 mg of water. In another experiment, 23.467 mg of the compound is reacted with excess oxygen to produce 10.142 mg of sulfur dioxide Add subscripts below to correctly identify the empirical formula of this compound (use this order of elements: CHSO) (use this order of elmensreily the empirical formula of ths copound CHSO

Explanation / Answer

In CO2, C content is 100 x 12g/44g = 27.27%

In water, H content is 100x2g/18 g = 11.1%

In SO2 , S content is 100 x 32g / 64 g = 50.0 %

In 25.121 mg sample there are:

44.751 mg x 27.27/100 = 12.204 mg C, or

                    100x 12.204 mg/44.751 mg = 27.27 % C

18.319 mg x 11.1/100 = 2.033 mg H, or

                    100x 2.033 mg/44.751 mg = 4.54 % H

In 23.467 mg sample there are:

10.142 mg x 50.0/100 = 5.071 mg C, or

                    100x 5.071 mg/23.467 mg = 21.61 % S

The % difference to 100% is O content : 46.58 %

Find the atomic ratio:

27.27 % C / 12 = 2.27

4.54 % H/ 1 = 4.54

21.61 %S/ 32 = 0.675

46.58 %O/ 16 = 2.91

Divide by the smallest (0.675) to find that

C:H:S:O is 3:6:1:4

C3H6S1O4

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