Hello, I am trying to complete the calculations portion of my lab This is for pr

Question

Hello, I am trying to complete the calculations portion of my lab

This is for properties of systems in chemical equilibrium

I am trying to find molarities and the Ksp (ie questions 4d.)

I attempted to add my data sheet but it would only allow the image sideways

Vol. .30 M Pb(NO3)2 = 5.0 ml moles Pb2+ = [M x V(stock] = 1.5 x 10^3 moles

Vol. .30 M HCl = 4 ml

Volume of H20 added, 3.0 ml, and Total volume of solution = 17.0 mL

SExperiment 22 Properties of Systems in Chemical Equilibrium-Le Chateller S Plinciple b. Explain your observations in Step 4. (lIn which direction did Reaction 5 shift when heated? Wha must have happened to the value of K, in the hot solution? What does this ell you about the sign of at does this tell you about the sign H in Reaction 5?) 3h-4d to ther ti disedvet into tro. Solution. PbC0g dissolved into He-Sol ton. PbC02Poit-CI with ncreased tempua ture ause hert as a regen Ehrets eachan to riqht, spit disappears water on [Pb2+1 and [CI ]? In what direction would such a change drive Reaction 5?) c. Explain why the PbCl, dissolved when water was added in Step 5. (What was the effect of d in Step 5. (What was the effect of the added l and ICI ]? In what direction would such a change drive Reaction 5?) wsadded b was added ecave the becase the iors cacthon dethuses, and hy le Cvateis Chetters n the roducty side of the eacthan decteuses, ond by le h Pwncipe, s0ed Phce dssaes to yaise -theil Cincertictan oqain d. Given the numbers of moles of Pb?+ and CI in the final solution in Step 5, and the volume of that ta ogaiM Eqwhbiwa Shifts to the left solution, calculate [Pb2 ] and ICI ] in that solution. [Pb2+ M; [CI] Noting that the molarities just calculated are essentially those in equilibrium with solid PbCl2, calculate IPb21 x ICIT. This is equal to Ksp for PbCl sp C. Complex lon Equilibria 1. Color of CoCl2 6 H,o Color in solution in 12 M HCI 2. Color in diluted solution 3. Color of hot solution vidlet Color of cooled solution Formula of Co(II) complex ion present in solution in a. 12 M HC1 ble

Explanation / Answer

  Moles Pb2+ = 5 x 0.30 / 1000 =0.0015
Moles Cl- = 4x 0.30 / 1000 = 0.0012
Total volume = 17.0 mL = 0.017 L
[Pb2+] = 0.0015 / 0.017 =0.0882 M
[Cl-] = 0.0012 / 0.017 = 0.0705 M
Ksp = [Pb+2][Cl-]^2
Ksp = [0.0882 M ](0.0705 M)^2
Ksp = 4.3 * 10^-4 M

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