A) Write the nuclear equation for the alpha decay of Polonium-215. B) For this a

Question

A) Write the nuclear equation for the alpha decay of Polonium-215.
B) For this alpha decay process, the half-life of Po-215 is 1.8e-3 seconds. Starting with 1g of Po-215, how much Po-215 will remain after 1 second?
C) Calculate the activity of 6.022e23 atoms of Po-215.
Please answer all the parts to the question A) Write the nuclear equation for the alpha decay of Polonium-215.
B) For this alpha decay process, the half-life of Po-215 is 1.8e-3 seconds. Starting with 1g of Po-215, how much Po-215 will remain after 1 second?
C) Calculate the activity of 6.022e23 atoms of Po-215.
Please answer all the parts to the question
B) For this alpha decay process, the half-life of Po-215 is 1.8e-3 seconds. Starting with 1g of Po-215, how much Po-215 will remain after 1 second?
C) Calculate the activity of 6.022e23 atoms of Po-215.
Please answer all the parts to the question

Explanation / Answer

A) 84Po215 ........>   82Pb211 + 2He4

B) given t1/2 = 1.8*10^-3 sec.

as we know radio active decay fallows first orderkinetics

so

   K = 0.693/t1/2

K = 0.693/1.8*10^-3

   K = 385 sec^-1

we know

K = 2.303/t log(initial/final)

385 = 2.303/1 log(1/final)

final = 6.71*10^-168 gm.

C)

A = K*N

A = 385*6.023*10^23

A = 2318.85 810^23 disintegrations per sec.

or

A = 2.32*10^26 disintegrations per sec.

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