For each of the following reactions, balance the chemical equation, calculate th

Question

For each of the following reactions, balance the chemical equation, calculate the emf, and calculate G° at 298 K. (Use the smallest possible coefficients for H2O(l), H+(aq), and HO-(aq). These may be zero.) (a) Aqueous iodide ion is oxidized to I2(s) by Hg22+(aq). I-(aq) + Hg22+(aq) + H+ I2(s) Hg(l) + H2O(l) emf V G° kJ (b) In basic solution Cr(OH)3(s) is oxidized to CrO42-(aq) by ClO-(aq). Cr(OH)3(s) + ClO-(aq) + OH-(aq) CrO42-(aq) Cl-(aq) + H2O(l) emf V G° kJ (c) In acidic solution copper(I) ion is oxidized to copper(II) ion by nitrate ion. Cu+(aq) + NO3-(aq) + H+(aq) Cu2+(aq) NO(g) + H2O(l) emf V G° kJ

Explanation / Answer

the emf calcualtion and G° requires Electrode potentials which are not given so i am just balancing the reactions.

a) 2I-(aq) + Hg22+(aq) + 0 H+ ------------> I2(s)   + 2Hg(l) + 0 H2O(l)

b) 2Cr(OH)3(s) + 3ClO-(aq) + 4OH-(aq)----------> 2CrO42-(aq) + 3Cl-(aq) + 5H2O(l)

c) Cu+(aq) + NO3-(aq) + 4H+(aq) ----------> Cu2+(aq)   + NO(g) + 2H2O(l

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