The conversion of natural gas, which is mostly methane, into products that conta

Question

The conversion of natural gas, which is mostly methane, into products that contain two or more carbon atoms, such as ethane (C2H6), is a very important industrial chemical process. In principle, methane can be converted into ethane and hydrogen: 2CH4(g)C2H6(g)+H2(g) In practice, this reaction is carried out in the presence of oxygen: 2CH4(g)+12O2(g)C2H6(g)+H2O(g).

Using the data in Appendix C in the textbook, calculate K for the first reaction at 25 C and 630 C.

Express your answers using one significant figure. Enter your answers numerically separated by a comma.

Explanation / Answer

we find dGo rxn

dGo rxn= dGo products - dGo reactants

          = dGo ( C2H6) + dGo ( H2O ) - 2 dGO ( CH4) - 12 dGO O2

          = -32.88 -228.61 - 2( -50.794) - 12 ( 0)

            = -159.9 KJ/mol = -159900 J/mol

we have dGo = -RT ln K

-159900 = -8.314 x 298 ln K

64.54 = ln K

K = exp ( 64.54)

= 1 x 10^28

( values of dGo taken from web since table is not provided here)

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