Part A A sample of gas in a balloon has an initial temperature of 9.0 C and a vo

Question

Part A

A sample of gas in a balloon has an initial temperature of 9.0 C and a volume of 2.01×10^3 L . If the temperature changes to 65 C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?

Part B

What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1 = 9.0 C , V1= 2.01×103 L ) to a volume of 4.02×103 L ? Assume no change in pressure or the amount of gas in the balloon.

Hint: Charles’s law states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas: V1T1=V2T2

Explanation / Answer

A) T1 = 9.0 C = 9.0 +273 K = 282 K

V1 = 2.01×10^3 L

T2 = 65oC = 65 +273 K = 338 K

V2 = ?

From Charles' law, V1/T1=V2/ T2

V2 = (V1/T1) x T2

= ( 2.01×10^3 L / 282 K) x (338 K)

= 2409 L

V2 = 2409 L

Therefore,  new volume, V2, of the gas = 2409 L

B)

T1 = 9.0 C = 9.0 +273 K = 282 K

V1 = 2.01×10^3 L

   V2 = 4.02×103 L

T2 = ?

From Charles' law, V1/T1=V2/ T2

T2 = (V2/V1) x T1

= (4.02×103 L /2.01×10^3 L ) x 282 K

= 564 K

= 564-273 oC

= 291 oC

T2 = 291 oC

Therefore,

required temperature = 291 oC

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