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The material covered in this homework assignment applies to processes that occur

ID: 974581 • Letter: T

Question

The material covered in this homework assignment applies to processes that occur at the Earth's surface. Equilibrium constants that you may need are given.Show all your work. A solution comprising 1557.4 mg L^-1 of HCO_3^- has a pOH of 4.9. Calculate the total concentration of carbonic acid in the solution. Determine whether water comprising 5 times 10^-3 mol L^-1 of Ca^2+ and 2times10^-3 mol L^-1 of F is saturated with respect to fluorite. If the above water is supersaturated, calculate the number of g L^-1 of fluorite that should precipitate when equilibrium is reached. Calculate the concentrations of all ions and the pH of a solution containing 0.001 moles of silicic acid (H_4SiO_4) per liter of solution. Silicic acid is a weak acid so you can treat it as a monoprotic acid. If the 0.001 moles silicic acid was added to a liter solution that had a pH of 4.2, what percentage of the silicic acid would dissociate?

Explanation / Answer

pOH = 4.9 (from this you can calculate pH). pH = 14-pOH = 9.1 pH = 9.1

The HCO3- reaction is

HCO3- H+ + CO32- with K2= 10-10.3

The CO32- generated on the past reaction will be the one that generate the H2CO3 in the solution, as it follows

H2CO3    H+ + HCO3-   with K1=10-6.35

For calculating the [HCO3-] you uses the K2 equation:

K2 = ([H+] * [CO32-]) / [HCO3-] from pH you can calculate [H+], and from stoichiometry you know that [H+] =[CO32-]

if pH = -Log [H+] => [H+] = 10-9.1 => [H+] = 7.94. Now you can calculate [HCO3-]

[HCO3-] = ([H+] * [CO32-]) / K2 = 1.25 x 10-8   

[HCO3-] = 1.25 x 10-8

Now that you knows [HCO3-] you put this information on the K1 equation (notice that [HCO3-] = [H+])

k1= [H2CO3] / [H+] * [HCO3-] =>  [H2CO3] = [H+] * [HCO3-] * k1 = 7.07 x 10-23

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