Had to repost due to these answers being incorrect in the origional posts The hy
ID: 974814 • Letter: H
Question
Had to repost due to these answers being incorrect in the origional posts
The hydrogen atom is not actually electronegative enough to form bonds to xenon. Were the xenon-hydrogen bond to exist, what would be the structure of XeH4? Double-click any atom and type Xe to change the label.
Draw the molecule by placing atoms on the grid and connecting them with bonds. Show all lone pairs of electrons
Draw a single Lewis structure for the phosphate ion (PO43), assuming that the phosphorus atom can expand its octet such that the formal charge on each of the atoms is minimized. Include all formal charges and lone-pair electrons.
Draw the Lewis structure for the NO2 ion. Include resonance structures. Draw the main Lewis structure of NOF.
Explanation / Answer
The electronic configuration of Xe is [Kr] 4d105s25p6
There are 8 valence electrons in Xenon. and there is 1 valence electron on each hydrogen and hence there are total of 12 electrons. Out of which, 8 eltrdons are shared giving rise to 4 bonds and remaiing are 4 electrons. There are two lone pairs od elctrons and along with 4 pairs of electrons form a square planar structure
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