Genetic problem: A form of gout us inherited as a recessive trait. In this disea
ID: 97538 • Letter: G
Question
Genetic problem: A form of gout us inherited as a recessive trait. In this disease, excess uric acid builds up on the blood and is deposited as ting crystals in the soft tissues of the limbs and around the joints. This causes very painful swelling somewhat resembling acute arthritis. Joe & belinda marry. Joe is homozygous normal & belinda is heterozygous (a carrier) for the disease. A) how likely are their children to have hereditary gout? B) if Joe were also a carrier, would half the children develop gout? Genetic problem: A form of gout us inherited as a recessive trait. In this disease, excess uric acid builds up on the blood and is deposited as ting crystals in the soft tissues of the limbs and around the joints. This causes very painful swelling somewhat resembling acute arthritis. Joe & belinda marry. Joe is homozygous normal & belinda is heterozygous (a carrier) for the disease. A) how likely are their children to have hereditary gout? B) if Joe were also a carrier, would half the children develop gout? Genetic problem: A form of gout us inherited as a recessive trait. In this disease, excess uric acid builds up on the blood and is deposited as ting crystals in the soft tissues of the limbs and around the joints. This causes very painful swelling somewhat resembling acute arthritis. Joe & belinda marry. Joe is homozygous normal & belinda is heterozygous (a carrier) for the disease. A) how likely are their children to have hereditary gout? B) if Joe were also a carrier, would half the children develop gout?Explanation / Answer
Sometimes the best way to figure out genetic issues is to use Punnet Squares.
If you let B be the normal, and b be the trait for gout, then Joe would be BB and Belinda would be Bb.
BB - Homozygous noraml and Bb - Heterozygous carrier.
BB X Bb
Gametes formed - B and B B and b.
A) Their children have a 50% chance of being a carrier for gout and a 50% chance of being normal. Their children would not have hereditary gout.
B) If Joe were also a carrier,so both are carrier and then half the children would not develop gout. 25% children would devlop gout.
Bb(carrier) X Bb(carrier)
Gametes formed - B and b B and b.
The children would have a 25% chance of having Gout, a 50% chance of being a carrier, and a 25% chance of being normal.
Male/Female B B B BB(normal) BB(normal) b Bb(carrier) Bb(carrier)Related Questions
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