Determine the theoretical yield of C when each of the following amounts of A and

Question

Determine the theoretical yield of C when each of the following amounts of A and B are allowed to react in the generic reaction:
A+2B3C

Part A

1 molA; 1 molB

Express your answer using two significant figures.

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Part B

1 molA; 3 molB

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Part C

2 molA; 2 molB

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Part D

32 molA; 68 molB

Express your answer using two significant figures.

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2)For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants.
4Cr(s)+3O2(g)2Cr2O3(s)

Part A

1 molCr; 1 molO2

Express your answer as a chemical formula.

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Part B

4 molCr; 2.5 molO2

Express your answer as a chemical formula.

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Part C

12 molCr; 10 molO2

Express your answer as a chemical formula.

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Part D

14.8 molCr; 10.3 molO2

Express your answer as a chemical formula.

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3)If the theoretical yield of a reaction is 20.4 g and the actual yield is 15.3 g , what is the percent yield?

4) For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants.
2Al(s)+3Br2(g)2AlBr3(s)

1.0 gAl; 1.0 gBr2

Express your answer as a chemical formula.

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Part B

2.2 gAl; 1.8 gBr2

Express your answer as a chemical formula.

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Part C

0.353 gAl; 0.482 gBr2

Express your answer as a chemical formula.

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Explanation / Answer

PartA:

1 mol A = 2 mol B = 3 mol C

yield of C from 1 mol A = 3 mol

yield of C from 1 mol B = 3/2 mol = 1.5 mol

So, B is the limiting reactant.

Theorerical yield of C is 1.5mol.

Part B:

yield of C from 1 mol A = 3 mol

yield of C from 3 mol B = 3*3/2 mol = 4.5 mol

So, A is the limiting reactant.

Theorerical yield of C is 3.0 mol.

Part C:

yield of C from 2 mol A = 6 mol

yield of C from 2 mol B = 2*3/2 mol = 3.0 mol

So, B is the limiting reactant.

Theorerical yield of C is 3.0 mol.

Part D:

yield of C from 32 mol A = 96 mol

yield of C from 8 mol B = 68*3/2 mol = 102 mol

So, A is the limiting reactant.

Theorerical yield of C is 96 mol.

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