TOCD, Southeast Chem /ibiscms/mod/ibis/view.php?id-2533192 WWW sapling learning.

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TOCD, Southeast Chem /ibiscms/mod/ibis/view.php?id-2533192 WWW sapling learning.com App Tarrant County Colle TCCD, Southeast-Ch Other bookmarks Print Calculator Periodic Table 30 Question 37 of 44 Map 32 A 0.160-mole quantity of NiCl2 is added to a liter of 1.20 M NH solution. What is the concentration of Nie 3 ions at equilibrium? Assume the formation consta of N s 5.5 x 108 33 Number 95 20 M 35 36 37 38 39 33 There is a hint available! View the hint by clicking on the bottom divider bar, Click on the divider bar again to hide the hi 43 Close AO Previous Give Up & View solution Ch Answer Next SExit Hint Copyright 2011 2016 Sapling Learning, Inc. 133 about careers partners privacy policy terms of use contact us help Ask me anything post REP INTERNSHIPS COLLEGES fast expert answer 3 Post up to 20 que per month ts typically answer Included in your Cheg hours Study subscription right Chegg Expert 7:41 PM 4/24/2016

Explanation / Answer

NiCl2(aq) + 6NH3(aq) <------> [Ni(NH3)6]Cl2(aq)

Kf = [Ni(NH3)6]Cl2/{[NiCl2]*[NH3]6}

Initially, [Ni(NH3)6]Cl2 = 0 M & [NiCl2] = 0.16 M & [NH3] = 1.2 M

Let at eqb., [Ni(NH3)6]Cl2 = x M & [NiCl2] = (0.16-x) M & [NH3] = (1.2-6x) M

Now, 5.5*106 = x2/{(0.16-x)*(1.2-6x)6}

Eqb. concentration of Ni2+ = (0.16-x)

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