Calculate the standard entropy, Delta S^degrees_rxn, of the following reaction a

Question

Calculate the standard entropy, Delta S^degrees_rxn, of the following reaction at 25.0 degrees C using the data in this table. The standard enthalpy of the reaction. Delta H^degrees_rxn, is -633.1 kJ- mol^-1. 3C_2H_2(g) rightarrow C_6H_6(l) Delta S^degrees_rxn = Then, calculate the standard Gibbs free energy of the reaction, Delta G^degrees_rxn. Delta G^degrees_rxn = Finally, determine which direction the reaction is spontaneous as written at 25.0 degrees C and standard pressure. forward reverse both neither

Explanation / Answer

Srxn = Sprod - Sreact = 269.2 - 3*200.9 = -333.5 J/molK

for

Grxn = H- TS

Grxn = -633.1*1000 - 298 * (-333.5 ) = -533717 J/mol =- 533.717 kJ/mol

since G <0, this goes forward direction spontanoulsy

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