HW 13 4/26/2016 11:55 PM A 5.4/10 4/25/2016 08:45 AM Print Calculator bed Period

Question

HW 13 4/26/2016 11:55 PM A 5.4/10 4/25/2016 08:45 AM Print Calculator bed Periodic Table estion 2 of 10 incorrect apling leaming At 1.00 atm and 0 , a 504 L mixture of methane (CH4) and propane (CyHs) was burned, producing 20.9 g of CO2. What was the mole fraction of each gas in the mixture? Assume complete combustion. Number X-ethane . 11.211 Number pa 263 There is a hint available! View the hint by dlicking on the divider bar again to hide the hint bottom divider bar on the Close O Previous Give Up & View Solution ) Check Answer 0 Next

Explanation / Answer

Moles of initial mixture = PV/RT

= 1 atm x 5.04 atm / 0.082 x 273.15 K

=0.225 moles

Moles of CO2 formed = 20.9 g /44 g/mol ==0.475 moles

1 mol CH4 form 1 mole CO2

1 mol C3H8 form 3 moles CO2

So, Total moles = 4 moles and ratio will be 1:3

So moles of CH4 = (1/4 x 0.475 moles ) = 0.11875 moles

Moles of C3H8 = (3/4 x 0.475 moles ) =0.35625 moles

Mole fraction of CH4 = 0.11875 / 0.475 = 0.25

Mole fraction of C3H8 = 0.35625 /0.475 = 0.75

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