Silver tarnish (Ag_2S) can be removed by immersing silverware in a hot solution

Question

Silver tarnish (Ag_2S) can be removed by immersing silverware in a hot solution of baking soda (NaHCO_3) in a pan lined with aluminum foil; however, foul-smelling hydrogen sulfide gas (h_2S) is produced. Which of the following statements is correct? E^o Silver/Silver(1) +0.799 Sulfur/hydrogen sulfide +0.141 Aluminum/aluminum(III) -1.662 Sodium/sodium(I) -2.713 Aluminum ions react with s^2-, form aluminum sulfide, and gaseous carbon dioxide is released. Silver ions in the presence of the baking soda (NaHCO_3 oxidize sulfide to elemental sulfur that attacks the aluminum foil, which produces aluminum sulfide. The aluminum acts as a reducing agent for the silver (I) in silver sulfide; then bicarbonate ion protonates the sulfide ion that is released. Aluminum is plated onto the silver surface, making it shiny again, and then the reaction of bicarbonate with aluminum oxide releases CO_2. Silver Ag_2S reduces the aluminum, becomes metallic silver in the process, and releases hydrogen sulfide, H_2S.

Explanation / Answer

3Ag2S + 2Al + 3H2O --> 6Ag +Al2O3 + 3H2S

3 NaHCO3(aq) + 3 H2S(aq) => 3 NaHS(aq)+3 H2O(l)+ 3 CO2(g)

so c is correct

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