Write the ion product expression for magnesium fluoride, MgF_2. [Mg^2+][F^-] [Mg

Question

Write the ion product expression for magnesium fluoride, MgF_2. [Mg^2+][F^-] [Mg^2+][F^-]^2 [Mg^2+][F^-]^2/[MgF_2(s)] 1/[Mg^3+][F^-] 1/[Mg^2+][F^-]^2 Calculate the solubility of silver oxalate. Ag_2C_2O_4, in pure water. K_sp = 1.0 times 10^-11 1.4 times 10^-4 M 8.2 times 10^-5 M 5.4 times 10^-5 M 3.2 times 10^-6 M 2.5 times 10^-12 M The solubility of lead (II) iodide is 0.064 g/100 mL at 20 degree C. What is the solubility product (Ksp) for lead (II) iodide? Which is more soluble in acidic solution than in pure water? Explain your answer. CH_3CH_2OH, ethanol Li_2O C_6H_12O_6, glucose

Explanation / Answer

5. ion product expression of MgF2

MgF2 = Mg+2 + 2F-

(b) [Mg+2][F-]2

6. Solubility of silver oxalate:

Ag2C2O4 = 2Ag+ + C2O42-

let the solubility of Ag2C2O4 = s, Ksp is the solubility product

Ksp = (s)(2s)2

Ksp = 4s3

1.0 x 10-11 = 4s3

s = 1.42 x 10-4 M

answer is a.

7. Molar mass of lead iodide = 461.01 g/mol

solubility of PbI2 = 0.064 g/100mL = 0.0064 g/L = 0.0064/461.01 M = 1.388 x 10-5 M

PbI2 = Pb+2 + 2I-

Ksp = (s)(2s)2

Ksp = 4s3

Ksp = 4 x (1.388 x 10-5)

Ksp = 1.07 x 10-14

8. b. Li2O is more soluble in acidic solution than in pure water.

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