Circle the result of each of the following conditions on the final calculated co

Question

Circle the result of each of the following conditions on the final calculated concentration of the vinegar sample. A student carrying out this laboratory found that the sample was not clear. But he continued to complete this titration. The Ksp would be calculated to be: Too High Too Low Unaffected The titration sample was seen to be cloudy so the student filtered it before titration. The Ksp would be calculated to be Too High Too Low Unaffected The titration sample was seen to be cloudy so the student heated it to dissolve the material and performed the titration. The Ksp would be calculated to be Too High Too Low Unaffected

Explanation / Answer

If Qsp is the ionic product and Ksp is the solubility product.

If Qsp > Ksp solution is supersaturated. And appear turbid i.e. not clear.

If Qsp < Ksp solution is unsaturated. And appear clear.

i) Sample was not clear i.e was turbid and it means it is supersaturated and hence Qsp > Ksp and hence Ksp would calculated to be too low.

ii) Sample seen to be cloudy i.e. turbid so originally solution is supersaturated but as it is filtered of now solution will be less unsaturated and hence Qsp < Ksp. Therefore Ksp calculated to be Too high.

iii) Solution was originally cloudy i.e. supersaturated and on heating turbidity get dissolved and solution is clear then Ksp calculated to be Too low.

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