The formula that is circle as seen above, why does it exists? What is the number

Question

The formula that is circle as seen above, why does it exists?

What is the number of fragments that must be cloned to ensure a high probability that desired sequence is present at least once in genomic library? -Allows to pr characterize single amino the protein ar roteins de no P = 1-(1-f)" P probability f- fraction of desired sequence in genome N- number of fragments Green-gene to Mismatched pri mutation) is ext N- Log(1-P)/Log(1-f) polymerase How many yeast DNA fragments of average length 5 kbp has to be clone to in order to have 99% probability that a genomic library contains certain sequence. Yeast genome: 12,1x106 bp. f= 5kbp/12100 kbp = 4.13x10-4 of yeast genome Altered gene is vector and expr bacteria, where serves as a temp new strands that mutated nucleoti N = log(1.99)/log(1-4.13104)-11,148 The Example of chi GST-fusion proteir protein of intere GST sequence is in alongside the ge Cassette mutation - Plasmid DNA is cut by restriction enzymes to remove a short sequence of bases and the new is added and ligated

Explanation / Answer

The number of clones depends upon the size of the genome f and average size of the cloned DNA.

If f is the fraction of the genome size compared to the average individual cloned fragment size and thus would represent the lowest possible no. of clones

f=genome size/fragment size

The no. of independent recombinants must be greater than f.In 1976 Clarke and Carbon derived a formula to calculate probablity(P) of including any DNA sequence in a random library of N independent recombinants.

The actual no. of clones to be calculated

N=In (1-P) / In(1-1/f)

N=no.of clones

P=probablity

Bigger the library better will be the chance of finding the gene of interest.

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