please and thank you! Given the velocity flow field V = x^2 i - 2xy j and the te
ID: 980069 • Letter: P
Question
please and thank you!
Given the velocity flow field V = x^2 i - 2xy j and the temperature field T (degreeK) = 300 - 2 x^2, determine: the acceleration vector a and acceleration magnitude for a fluid particle at the point (x,y) = (2,3); the rate of change of temperature following a fluid particle at any x,y and then evaluate DT/Dt at the point (2,3); the equation for the streamline y = f(x) passing thru the point (1,2); If a fluid particle passes thru (1,2) at what coordinate x will y = 0.5 m and what is At to get there from (1,2)?Explanation / Answer
The velocity flow V=x2 i-2xy j
Temperature field T(oK) = 300-2x2
At (2,3)
When x =2 and y=3
V=22 i - 2x2x3 j = 4i-12j
T=300-2x22 = 292 K
i=-1
V=-4-12j = -16j
(b) at 2,3 -25oK/s
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