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PLease answer both questions. What is the by mass of a solution created with 39.

ID: 980181 • Letter: P

Question

PLease answer both questions.                                                                                                                                                                                                                                                                                                                                                                                                                                      

What is the by mass of a solution created with 39.6 g of C6H1206dissolved in 482 g of water to make 555 mL of solution? Assume density E 1.00 g/mL QUESTION 4 1 points Save Answer A person is considered medically to have lead poisoning if they have a concentration of greater than 5.1 ug (micrograms) of lead per deciliter of blood. What is the concentration in parts per billion (ppb)? Assume 1 mL of blood weighs 1 g.

Explanation / Answer

1) mass% = (mass of component/mass of solution)*100

Thus, mass % of C6H12O6 = {mass of C6H12O6 /(mass of C6H12O6 + mass of water)}*100 = (39.6/521.6)*100 = 7.592 %

2) ppb = 1 in 109

1 deciliter = 0.1 litres = 100 ml

Thus, concentration of Pb = 5.1*10-6 /100 ml

Thus concentration in ppb = 5.1*10-6*107 = 51

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