A) Suppose that 0.83 g of water condenses on a 85.0 g block of iron that is init

Question

A) Suppose that 0.83 g of water condenses on a 85.0 g block of iron that is initially at 20 C.

If the heat released during condensation goes only to warming the iron block, what is the final temperature (in C) of the iron block? (Assume a constant enthalpy of vaporization for water of 44.0 kJ/mol.)

B)Suppose that 1.13 g of rubbing alcohol (C3H8O)evaporates from a 66.0 g aluminum block.If the aluminum block is initially at 25 C, what is the final temperature of the block after the evaporation of the alcohol? Assume that the heat required for the vaporization of the alcohol comes only from the aluminum block and that the alcohol vaporizes at 25 C. Heat of vaporization of the alcohol at 25 C is 45.4 kJ/mol

Explanation / Answer

Qwater = LH*m

Qiron = m*Cp*(Tf-Ti)

Qiron = 85*0.450*(Tf-20)

Qwater = 4400/18 * 0.83 = 202.8888 J

then

Q iron = - qwater = 202.8888

85*0.450*(Tf-20) = 202.89

Tf = 202.89/85*0.450 + 20 = 21.074123 °C

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