the final mass of calcium oxalate monohydrate, CaC2O4 * H2O was 0.5126g. to the
ID: 980287 • Letter: T
Question
the final mass of calcium oxalate monohydrate, CaC2O4 * H2O was 0.5126g. to the correct number of significant figures, what is the molar concentration of Ca2+ in the unknown solution? the final mass of calcium oxalate monohydrate, CaC2O4 * H2O was 0.5126g. to the correct number of significant figures, what is the molar concentration of Ca2+ in the unknown solution? the final mass of calcium oxalate monohydrate, CaC2O4 * H2O was 0.5126g. to the correct number of significant figures, what is the molar concentration of Ca2+ in the unknown solution? the final mass of calcium oxalate monohydrate, CaC2O4 * H2O was 0.5126g. to the correct number of significant figures, what is the molar concentration of Ca2+ in the unknown solution?Explanation / Answer
0.5126g
CaC2O4*H2O --> H2O + C2O4-2 + Ca+2
MW = CaC2O4 + H2O = 128.097 + 18 = 146.097
mol = mass/MW = 0.5126/146.097 = 0.003508627 mol of CaC2O4*H2O
assume 1 mol of CaC2O4*H2O will give 1 mol of Ca+2
then
0.003508627 mol of Ca+2 is present
the solutoin has 4 significant numbers so
0.003509 M (assuming 1 Liter solution)
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