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CH2O acetic acid NaOH mass 34.087 grams P2O5 mass 38.294 grams Added grams of ca

ID: 980737 • Letter: C

Question

CH2O acetic acid

NaOH mass 34.087 grams

P2O5 mass 38.294 grams

Added grams of catechol 4.867 grams

Combustion after catechol added of NaOH 45.754 grams P2O5 40.682

Next unkown substance added 5.140grams

combustoion after unknown added NaOH 56.518 grams P2O5 42.883 grams

The mass of O in your sample can be obtained by the difference of the sample mass and the total calculated masses of H and C. Calculate the mass and then the number of moles of O atoms in the Catechol sample.

mass of O atoms?

moles of O atoms?

19. DISCUSSION From the change in the P2Os trap mass before and after reaction, determine the mass of H2O produced by combustion of your catechol sample. Be careful to use the change in mass of each trap for just before, and just after, the catechol sample is combusted mass of H20 2.388 Similarly, determine the mass of CO2 produced from the mass change in the NaOH trap after combustion of catechol mass of co 11.667 Convert the above masses into the number of moles of H2O and CO2 produced from your catechol sample moles of H20 130 moles moles of Co2 265 moles From the number of moles of H20 and CO2 produced, determine the number of moles of H atoms and C atoms in the catechol sample and enter below moles of H atoms 260 moles moles of C atoms 265 moles From the above and the atomic masses of the elements, determine the mass of H and C in your sample mass of H atoms 260 mass of C atoms 3.18 ANSWERED - CHANGES ALLOWED

Explanation / Answer

Honestly I don't understand very well the experiment you are doing or even the overall reaction, Could you please provide the infor for that?. In this way I can confirm your results.

Meanwhile, I'll work with your results, assuming you have the correct values and what I understand,

m of oxygen, if sample is 5.140 then:

m O2 = 5.140 - 0.260 g - 3.18 g = 1.7 g of O2

moles of O2 = 1.7 g / 32 g/mol = 0.0531 moles

If there's anything you need to be fixed, according to your values, and the whole experiment, please let me know in a comment and I'll fix it for you.

Hope this helps

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