1. A sample of a gas has a pressure of 854 torr at 288 °C. To what Celsius tempe
ID: 981960 • Letter: 1
Question
1. A sample of a gas has a pressure of 854 torr at 288 °C. To what Celsius temperature must the gas be heated to double its pressure if there is no change in the volume of the gas?
2.Before taking a trip, you check the air in a tire of your automobile and find it has a pressure of 42 lb in-2 on a day when the air temperature is 16°C (about 61oF). After traveling some distance, you find that the temperature of the air in the tire has risen to 43°C (approximately 109°F). What is the air pressure in the tire at this higher temperature, expressed in lb in-2?
3. When 238 mL of oxygen at 773 torr and 19.0°C was warmed to 31.2°C, the pressure became 792 torr. What was the final volume (in mL)?
Explanation / Answer
1. A sample of a gas has a pressure of 854 torr at 288 °C. To what Celsius temperature must the gas be heated to double its pressure if there is no change in the volume of the gas?
Solution :- P1= 854 torr
T1 = 288.0 C +273 = 561 K
P2 = 2*854 torr = 1708 torr
T2 = ?
P1/T1 = P2/T2
T2= P2*T1 / P1
=1708 torr * 561 K / 854 torr
= 1122 K
1122 K -273 = 849 C
So the final temperature is 849 oC
2.Before taking a trip, you check the air in a tire of your automobile and find it has a pressure of 42 lb in-2 on a day when the air temperature is 16°C (about 61oF). After traveling some distance, you find that the temperature of the air in the tire has risen to 43°C (approximately 109°F). What is the air pressure in the tire at this higher temperature, expressed in lb in-2?
Solution :- P1 = 42 lb in-2
T1 = 16 C +273 = 289 K
P2 = ?
T2 = 43 C +273 =316 K
P1/T1 = P2/T2
P2 = P1*T2/T1
= 42 lb in-2 * 316 K / 289 K
= 45.92 lb in-2
So the pressure is 45.92 lb in-2
3. When 238 mL of oxygen at 773 torr and 19.0°C was warmed to 31.2°C, the pressure became 792 torr. What was the final volume (in mL)?
Solution :-
V1 = 238 ml
T1 = 19.0 C +273 = 292 K
P1 = 773 torr
T2 = 31.2 C +273 = 304.2 K
P2 = 792 torr
V2 = ?
Formula
P1V1/T1 = P2V2/T2
V2 = P1V1*T2 / T1P2
= 773 torr * 238 ml * 304.2 K / 292 K *792 torr
= 242 ml
So the final volume is 242 ml
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