Question 1 0/1 pts What decides when absorption spectroscopy is used versus emis

Question

Question 1 0/1 pts What decides when absorption spectroscopy is used versus emission spectroscopy for the detection of metal ions in solution? It doesn't really matter. Emission spectroscopy and absorption spectroscopy are equally well suited to detecting any metal ions in solution Absorption spectroscopy is only used for the detection of iron ions in solution. Emission spectroscopy is used for all other metal ions Absorption spectroscopy is only used for the detection of chromium ions in solution. Emission spectroscopy is used for all other metal ions. Emission spectroscopy is used when a solution containing metal ions is colorless and absorption spectroscopy is used when the solution containing metal ions is colored

Explanation / Answer

Answer:

Question 1).

It does not really matter.Emission spectroscopy and absorption spectroscopy are equally well suited in detecting metal ions in solution.

Question 2).

According to M1V1 = M2V2

Where:

M1 = 400 ppm

M2 = M

V1 = 7.50 mL

V2 = 10 mL

M1V1 = M2V2

400*7.5 = M*10

M = (400*7.5)/10

= 300 ppm

Question 3).

According to M1V1 = M2V2

Where:

M1 = 400 ppm

M2 = M

V1 = 5 mL

V2 = 10 mL

M1V1 = M2V2

400*5 = M*10

M = (400*5)/10

= 200 ppm

Question 4).

According to M1V1 = M2V2

Where:

M1 = 400 ppm

M2 = M

V1 = 2.50 mL

V2 = 10 mL

M1V1 = M2V2

400*2.5 = M*10

M = (400*2.5)/10

= 100 ppm

Question 5).

According to M1V1 = M2V2

Where:

M1 = 100 ppm

M2 = M

V1 = 5.0 mL

V2 = 10 mL

M1V1 = M2V2

100*5 = M*10

M = (100*5)/10

= 50 ppm

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