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Question

ooo Verizon 12:54 AM RBELMONT96 MyscrapNook" & EZ create Facebook Email widTangent Gan university of apply. b university of serida apply- e see what'sHet tv2ova florida levation and Freezing-Point Depression for Solutions in Water Ethylene glycol, the primary ingredient nanttreeze, has te demical formula CrHsor The ra ng- A half-and-half moture of water and antifreeze ater What is the freezing point of radiator fiuid that is 50% antheeze by mass? Part A Kr for water is 186 C/m appropriate units. Express your answer to three significant figures and include the and the Part B is 0 512 Write a message

Explanation / Answer

A) consider 100 g of solution

given 50 % is C2H602

so

mass of C2H602 = 50 g

mass of water = 50 g

now

we know that

moles = mass / molar mas s

also

molar mass of C2H602 = 62 g/mol

so

moles of C2H602 = 50 / 62 =0.80645

now

we know that

molality = moles of C2H602 x 1000 / mass of water (g)

so

molality = 0.80465 x 1000 / 50

molality = 16.13

so

now

we know that

depression in freezing point is givne by

dTf = kf x m

so

dTf = 1.86 x 16.13

dTf = 30

now

dTf = freezing point of pure water - freezing point of solution

so

0 - T = 30

T = -30

so

the freezing point is -30 C

B)

now

elevation in boiling point is

dTb = kb x m

so

dTb = 0.512 x 16.13

dTb = 8.26

so

T + 100 = 8.26

T = 108.26

so

the boiling point is 108.26 C

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