Considerr the following reaction 2NH_3(g) + 2O_2(g) rightarrow N_2O(g) + 3H_2o(1

Question

Considerr the following reaction 2NH_3(g) + 2O_2(g) rightarrow N_2O(g) + 3H_2o(1) triangleH degree = -683kJ triangleS degree = -366J/K. Above or below what temperature (K) would triangleG degree of the above be less than zero? {circle your choice and provide the value} Above/Below (b) [6] Considerr the reaction: N_2(g) + 3H_2(g) rightarrow 2NH_3(g) Calculate triangleG for this reaction at 298.15K if the pressure of NH-3(g) is reduced to 24.64 mm Hg while the pressures of N_2(g) and H_2(g) remain at 1 atm.

Explanation / Answer

a)

G < 0

then

G = H - TS

H - TS <0

H < TS

T > H/S

T > (-683000)/-366 = 1866.12021858

this must be below so

H - TS < 0

since T is always positive and S is negative

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