a. A commercial antacid was analyzed to determine the amount of antacid present

Question

a. A commercial antacid was analyzed to determine the amount of antacid present in the sample. Complete table for l of the analysis (see Report sheet) Record calculated values with the correct figures. A. Dissolving the Antacid -0.20L Part 1 3. Mass of antacid sample (g) 4. Total volume of HCI added (ml) 5. Molar concentration of HCI (molt) 0.0978. B. Analyzing the Antacio Sample 1. Molar concentration of NaOH (movi) 00902. Part C.2 2. Buret reading, initial (ml) 10.60 3. Buret reading final (nL) 4. Volume of NaOH added (mL) Part C3 C. Calculations 1. Moles of HCI added, total (mo) 2. i ales of NapH added (no) a os of base in antacid sample (mol Part C4 mo base in antacid move) mass of antacid sample b. For Trials 2 and 3, the mol base in antacid were 8.22 x 10 and 1.05 x 10 respectively. mass of antacid sample a. What is the average mol base in antacid of the antacid sample mass of antacid sample b. What are the standard deviation deviation (%RSD) for antacid sample? and the relative standard mol base in antacid of mass of antacid sample

Explanation / Answer

Volume of NaOH added (mL) = 10.6 - 3.85 = 6.75 mL

Moles of HCl added = 0.0978 mol/L * 0.025L = 0.002445 mol

Moles of NaOH added = 0.0902 mol/L * 0.00675 L = 0.0006 mol

The moles of base in antacid will be the moles present at the beginning minus the moles present after neutralizing:

0.002445 mol of HCl - 0.0006 = 0.001845 moles consumed by antacid

Stoichiometry states that one mole of antacid consumes 2 of HCl, which means, we have 0.009225 moles of base

Ratio = 0.009225 mol/0.204g = 4.522 x 10-3

Average = 7.75 x 10-3

Std deviation = 0.003

Relative std. deviation = 0.3894

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