Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

tivity do CHEM 110 Spring 2016 Sect. O cengageBrain . My Horne (,\' Owix2 Iine t

ID: 983853 • Letter: T

Question

tivity do CHEM 110 Spring 2016 Sect. O cengageBrain . My Horne (,' Owix2 Iine teaching-x Use the Referesces to access important valees if needed for thi qaestion. For the following reaction, 3.14 grams of exygen gas are mixed with excess butane (C,Hia) The reaction yields 1.77 grams of carbon diexide butane (C H) g+ esygrn () carboa dioxide ()+water (a) What is the theoretical yield of carbon dieside ? What is the percent yield of carbon dioxide grams Slbenit Answer Retry Entire Group 3 more group attempts remaining

Explanation / Answer

Part A.

balanced equation : 2C4H10 + 13O2 ---> 8CO2 + 10H2O

moles of O2 = 3.14 g/32 g/mol = 0.098 mols

13 moles of O2 gives 8 moles of CO2

So moles of CO2 produced by 0.098 mol O2 = 0.098 x 8/13 = 0.06 mols

theoretical yield of CO2 = 0.06 mol x 44.01 g/mol = 2.66 g

Percent yield of CO2 = (1.77/2.66) x 100 = 66.54%

Part B.

balanced equation : SiF4 + 4H2O ---> 4HF + SiO2

moles of SiF4 = 3.09 g/104.08 g/mol = 0.03 mols

1 mole of SiF4 produces 4 moles of HF

So moles of HF produced by 0.03 mols of SiF4 = 0.12 mols

Theoretical yield of HF = 0.12 mol x 20.01 g/mol = 2.38 g

Percent yield of HF = (2.16/2.38) x 100 = 90.76%