Suppose that in part II, step 3, a student did not completely dissolve the urea

Question

Suppose that in part II, step 3, a student did not completely dissolve the urea sample, Will the freezing point depression, Delta T_f, of the solution be larger or smaller than it would have been if the compound was of the solution be larger or smaller than it would explanation compound was dissolved completely? Justify your answer with an Will the calculated freezing point depression constant, Kf, be larger or smaller than it would have been if the compound was dissolved completely? Justify your answer with an explanation.

Explanation / Answer

Answer – a) We know when the solute is dissolved completely, then there are particles in the solution and the disorder of the solution increase and there is freezing point depression also increased, but if the solute is not dissolved completely then there is less number of particle than expected with completely dissolved. So as the less number of particle there is less molality and that affect the freezing point depression will be small than expected.

b) When the solute is dissolved completely, then there are particles in the solution and the disorder of the solution increase and there is freezing point depression increased and also increased the freezing point depression constant, since we know Kf = Tf/m. The freezing point depression and its constant are directly proportional to each other, so when the solute is not dissolved completely then there is smaller freezing point depression and hence smaller freezing point depression constant than expected.

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