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Just need help with the first part. xwwN9579: Practice 10 Chemistry question l C

ID: 988142 • Letter: J

Question

Just need help with the first part.

xwwN9579: Practice 10 Chemistry question l Che- x Dora × Li smartwork.wwnorton.com/sw/mod/smartwork/view.php?id-517308&isStudent-l; Calculate the root-mean-square speed of radon at 25°C in meters per second. How does the result compare to the root-mean-square speed of nitrogen under the same conditions (515 m/s)? Select the primary reason for the difference 4ms of radon: 4ms of radon is than that of N2. Primary reason for the difference: Number O pressure O higher volume temperature molar mass m/ s lower O solubility Hint Check Answer ? View Solution

Explanation / Answer


RMS velocity = sqrt(3RT/M)

   radon RMS velocity = sqrt(3*8.314*298 / (222*10^(-3)))

    = 182.98 m/s

N2 RMS velocity = sqrt(3*8.314*298 / (28*10^(-3)))

     = 515 m/s.

radon RMS velocity is less than that of N2. due to difference in molarmass