So far, in thinking of energy changes in biochemical reactions, our emphasis has

Question

So far, in thinking of energy changes in biochemical reactions, our emphasis has been on the free energy change in the biochemical standard state, that is, on dGo'. This is directly related to the equilibrium constant, Keq' (see text, handout or video, or all three (!)). Let's calculate an equilibrium constant. I'll give you a dGo' value. Suppose that dG0' for the hydrolysis of acetylcholine (to acetate and choline) is -9.2 kJ/mol. What is dGo' for acetylcholine hydrolysis? (Assume 25oC and 1 atmosphere pressure -- or just use the formula in my posting on free energy changes.) What is the value of Keq' for the hydrolysis of acetylcholine?

g

Explanation / Answer

Relation between dG0 and Keq is:

dG0 = - RT ln Keq

- 9.2 kJ/mol = - 8.314 J.K­1.mol-1 * 298 K * ln Keq

or, 9200 J/mol = 8.314 J.K­1.mol-1 * 298 K * ln Keq

or, Keq = 41

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