please double check these answers because I do not want to get them wrong. tion
ID: 988369 • Letter: P
Question
please double check these answers because I do not want to get them wrong.
Explanation / Answer
1 of 13
Step 1 : H2O(s) at -10 oC to H2O(s) at 0 oC
q1 = mCpdT = 85 x 2.087 x 10 = 1.77 kJ
step 2 : H2O(s) at 0 oC to H2O(l) at 0 oC
q2 = mdHf = (85/18.02) x 6.02 = 28.40 kJ
step 3 : H2O(l) at 0 oC to H2O(l) at 100 oC
q3 = mCpdT = 85 x 4.18 x 100 = 35.53 kJ
step 4 : H2O(l) at 100 oC to H2O(g) at 100 oC
q4 = mdHv = (85/18.02) x 40.7 = 192 kJ
step 5 : H2O(g) at 100 oC to H2O(g) at 147 oC
q5 = mCpdT = 85 x 2.01 x 47 = 8.03 kJ
Total heat required = q1 + q2 + q3 + q4 + q5 = 265.7 kJ
2 of 13
heat q added = 625 cal = 2617 J
q = mCpdT
2617 = 5 x 2.087 x (Tf -(-20)) + (5/18.02) x 6.02 x 1000
Tf = 88.72 oC
9 of 13
1 mole of metal produces 1 mole of H2
moles of H2 = PV/RT = (756/760) atm x 0.277 L/0.08206 L.atm/K.mol x 298 K = 0.011 mol
Molar mass of metal = 0.265 g/0.011 mol = 24.09 g/mol
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