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please double check these answers because I do not want to get them wrong. tion

ID: 988369 • Letter: P

Question




please double check these answers because I do not want to get them wrong.

tion 1 of 13 At 1 atm, how much energy is required to heat 85.0 g of H,O(s) at-10.0 'C to H-O(g) at Number Question 2 of 13 saping lparring 625 cal of heat is added to 5.00 g ice at-200°C. What is the final temperature of the water? Values for Water specific heat of H2O(s)|2.087 J/(g-o Ca Speclfic heat of H0 4.184 Jg 'c) Number 230.cl °C Heat of fusion for H2O 333.6 J/g Question 3 of 13 sapling leaming If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, whic these choices shows a hydrogen bond? Check all that apply

Explanation / Answer

1 of 13

Step 1 : H2O(s) at -10 oC to H2O(s) at 0 oC

q1 = mCpdT = 85 x 2.087 x 10 = 1.77 kJ

step 2 : H2O(s) at 0 oC to H2O(l) at 0 oC

q2 = mdHf = (85/18.02) x 6.02 = 28.40 kJ

step 3 : H2O(l) at 0 oC to H2O(l) at 100 oC

q3 = mCpdT = 85 x 4.18 x 100 = 35.53 kJ

step 4 : H2O(l) at 100 oC to H2O(g) at 100 oC

q4 = mdHv = (85/18.02) x 40.7 = 192 kJ

step 5 : H2O(g) at 100 oC to H2O(g) at 147 oC

q5 = mCpdT = 85 x 2.01 x 47 = 8.03 kJ

Total heat required = q1 + q2 + q3 + q4 + q5 = 265.7 kJ

2 of 13

heat q added = 625 cal = 2617 J

q = mCpdT

2617 = 5 x 2.087 x (Tf -(-20)) + (5/18.02) x 6.02 x 1000

Tf = 88.72 oC

9 of 13

1 mole of metal produces 1 mole of H2

moles of H2 = PV/RT = (756/760) atm x 0.277 L/0.08206 L.atm/K.mol x 298 K = 0.011 mol

Molar mass of metal = 0.265 g/0.011 mol = 24.09 g/mol