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Safari File Edit View History Bookmarks Window Help 63% Sun 7:45 PM Q EE O O Take Test: Online Quiz #1 CHEM-2255-003-89424-SP-2016 ses.cscc.ed webapps/assessment/take/launch jsp?cou e assessment id 445578 1&course; id 108901 1&content; id L7404321 1&step; nu Reade CO Statistics f... I Chegg. MEN CORDUR. I UNIQLO Evolution Ec... I StudyBlue Calculus 1 ...s YouTube CNCPTs Timberland iphixc Calculus 1 ...s YouTube %201.pdf Online quiz CHEM-2255-0003-89424-SP Take Test: Online Quiz #1 CHEM-2255 Inbox (8) mahdiwarsa00@gmail.com Chegg.com Recrystallization resulted in the pure product. There is no way to determine whether or not the recrystallization resulted in a loss of yield without mass data. Recrystallization resulted in a pure sample of the starting material. 4 points Save Answer QUESTION 6 Consider the reaction shown below: HNO H2SO4 NO2 Remaining Time 1 hour 13 minutes, 57 seconds. resonances in the 1HNMR (don't count spin-spin splitting) The starting material would have The product would have Question Completion Status: resonances in the C NMR ab QUESTION 7 4 points Saved After running the reaction shown in question 6, the product is purified by recrystallization with methanol. A 1H NMR is run with the following results 3.42 (3H, s), 3.97 (1H, s), 4.00 (3H, s), 7.68 (1H, dd), 8.38 (1H, d), 8.43 (1H, d), 8.86 (1 H, s What conclusions can be made? C. The NMR data provides evidence that the methanol was not completely evaporated from the sample. O The NMR data is consistent with what would be expected for the pure product.

Explanation / Answer

Answer – There are given, starting material and product. The starting material is ester and the resonance in the 1HNMR means the total number of signals in the 1HNMR and not the splitting lime triplet or doublet. The same for the 13CNMR for the resonance signals as follow –

The starting material would have 4 resonances in the 1HNMR.

The product would have 6 resonances in the 13CNMR

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