For the following questions, consider a solution prepared by dissolving 148g NaC

ID: 988892 • Letter: F

Question

For the following questions, consider a solution prepared by dissolving 148g NaCl into 2000.0 grams of water.

Part E - How many moles of NaCl are in this solution?

Part F - What is the molal concentration (molality) of NaCl in this solution?

Part G - How many moles of ion-particles are there in this solution of NaCl?

Part H - What is the molal concentration (molality) of ion-particles in this solution?

Part I - Calculate the increase in boiling point for this solution (compared to pure water).

Part J - Given that the normal boiling point of pure water is 100.0C (at 1 atm pressure), what is the boiling point of this solution?

2000.0 grams of water= 1998 mL of water (density=0.999 g/mol)

Step #1 - Convert grams of solute to moles of solute:

(148 g of NaCl x 1 mol of NaCl)/ 58.44 g/mol= 2.5325 mol of NaCl (Part E)

Step 2 – Divide moles of solute by liters of solution:

2.5325 mol of NaCl / 1.998 L= 1.2675 M of NaCl (Part F)

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