1.) What is the \"molarity\" of a solution prepared by dissolving 1.325 grams of

Question

1.) What is the "molarity" of a solution prepared by dissolving 1.325 grams of sodium carbonate in 250.00mL of water?


2.) What is the "molality" of a solution of 5.25g of urea is dissolved in 500.0 toluene l. Molecular weight of urea= 60.0 amu and the molecular formula of toluene is C7H8







1.) What is the "molarity" of a solution prepared by dissolving 1.325 grams of sodium carbonate in 250.00mL of water?


2.) What is the "molality" of a solution of 5.25g of urea is dissolved in 500.0 toluene l. Molecular weight of urea= 60.0 amu and the molecular formula of toluene is C7H8










2.) What is the "molality" of a solution of 5.25g of urea is dissolved in 500.0 toluene l. Molecular weight of urea= 60.0 amu and the molecular formula of toluene is C7H8

Explanation / Answer

1)

molarity is given by no. of mokes of solute per litre of solution.

step 1 is to find out the no. of moles of sodium carbonate:

molar mass=105.98 g

no. of moles=1.325/105.98= 0.0125

molarity= 0.0125/0.25 = 0.05 M

2)

molaity is the no, of moles of solute per kg of solvent.

moles of urea= 5.25/60 = 0.0875

molality= 0.0875/0.5= 0.175 m

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