help??? The following mechanism has been proposed for the recombination of atoms

Question

help???

The following mechanism has been proposed for the recombination of atoms A and B involving buffer gas M overall reaction: A + B + M AB + M Derive the steady state rate law for this mechanism and circle your results: Under limiting conditions of high concentrations of B, the rate law will reduce to (CIRCLE ONE) first order in A and second order in M, total third order first order in A, M, and B, total third order first order in A and first order in M; total second order first order in A and first order in B; total second order first order in B, total first order.

Explanation / Answer

a) rate of formation of AM = k1*[A]*[M]

rate of consumption of M = k2*[AM]*[B]

Since rate of formation = rate of consumption of intermediate in a steady state approximation , therfore,

k1([A]*[M] = k2*[AM]*[B]

or, [AM] = {k1([A]*[M]}/{k2*[B]}

Now, d[AB]/dt = k2*[AM]*[B] = k1([A]*[M]

b) The correct option is :- first order in A , first order in M ; total second order.

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