In the following reaction it was found that 880 grams of carbon dioxide is forme

Question

In the following reaction it was found that 880 grams of carbon dioxide is formed C_5H_12 + 8O_2 rightarrow 5CO_2 + 6H_2O Calculated how many grams of pentane C_5H_12 reacted. Calculated how many grams of water is formed. Calculated how many grams of oxygen gas O_2 reacted. In the following reaction 702 grams of aluminum carbonate was used to react phosphoric acid. Al_2(CO_3)_3 + 2H_3PO_4 2AlPO_4 + 3CO_2 + 3H_2O Calculate how many grams of aluminum phosphate will be formed. Calculate how many grams of acid will react. Calculate how many grams of water will be formed. Calculate how many grams of carbon dioxide will be formed.

Explanation / Answer

9)

mol CO2= 880g/(12 +(16x2))g/mol= 20mol

a) 5 mol of CO2 are produced by 1 mol of pentane, so, 20 mol of CO2 are produced by 4 mol of pentane.

mass pentane= mol x MW = 4mol x (5x12 + 12x1)g/mol= 288g

b) When 5 mol of CO2 are produced 6 mol of H2O are produced too, so, when 20 mol of CO2 are produced, 24 mol of H2O are produced.

mass= 24mol x 18g/mol= 432g

c) 5 mol CO2 are produced by 8 mol of O2, so, 20 mol of CO2 is produced by 32 mol of O2.

mass= 32mol x 32g/mol= 1024g

10)

a) mol Al2(CO3)3= 702g/234/mol= 3mol

a) 1 mol of aluminum carbonate forms 2 mol aluminum phosphate, so, 3 mol aluminum carbonate froms 6 mol aluminum phosphate.

mass= 6 mol x 122g/mol= 732g

b) 1 mol of Al2(CO3)3 reacts with 2 moles of acid, so 3 mol Al2(CO3)3 react with 6 moles of acid.

mass= 6mol x 98g/mol= 588g

c) 1 mol Al2(CO3)3 produces 3 mol of water, so, 3 mol of Al2(CO3)3 produces 9 mol of water.

mass= 9mol x 18g/mol= 162g

d) 1 mol Al2(CO3)3 produces 3 mol of CO2, so, 3 mol of Al2(CO3)3 produces 9 mol of CO2.

mass CO2= 9mol x 44g/mol= 396g

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