I don\'t understand how to get the order for B and C 26. Consider the following
ID: 992780 • Letter: I
Question
I don't understand how to get the order for B and C
26. Consider the following data for the reaction:
2 A + 2B + C ===> D + 2 E
Exp
Initial [A]
Initial [B]
Initial [C]
Initial Rate M/s
1
0.024
0.085
0.032
6.0 x 10-6
2
0.096
0.085
0.032
9.6 x 10-5
3
0.024
0.034
0.080
1.5 x 10-5
4
0.012
0.170
0.032
1.5 x 10-6
What is the order with respect to each reactant? A-2nd B-0th C-1st
Calculate the rate constant. 0.33 M-2s-1
Write the rate law for this reaction. rate = k [A]2[C]
Exp
Initial [A]
Initial [B]
Initial [C]
Initial Rate M/s
1
0.024
0.085
0.032
6.0 x 10-6
2
0.096
0.085
0.032
9.6 x 10-5
3
0.024
0.034
0.080
1.5 x 10-5
4
0.012
0.170
0.032
1.5 x 10-6
Explanation / Answer
The reaction is:-
2A + 2B + C = D + 2E
Since this is an elementary reaction, its rate law can be written as---
Rate = K[A]2[B]2[C]
The order with respect to A is 2, with respect to B is 2 and with respect to C is 1.
For experiment no. 1.
6.0 x 10-6 = K1 x [0.024]2 x [0.085]2 x 0.032 ;
or, K1 = 45.055
For experiment no. 2.
9.6 x 10-5 = K2 x [0.096]2 x [0.085]2 x 0.032
or, K2 = 45.055
For experiment no. 3.
1.5 x 10-5 = K3 x [0.024]2 x [0.034]2 x 0.080
K3 = 281.59
For experiment no. 4
1.5 x 10-6 = K4 x [0.012]2 x [0.170]2 x 0.032
K4 = 11.2636
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