DETERMINATION OF MANGANESE IN STEEL Primary standard solution: O lOH mg Mn/mL (C
ID: 993675 • Letter: D
Question
DETERMINATION OF MANGANESE IN STEEL Primary standard solution: O lOH mg Mn/mL (Cotd") lO1H mg Mn/mL (Cstd Steel sample: 1083 Steel sample: l0835 mg steel 0 mL solution stemL solution Measurements A 5,00 .000.3 .gol .gol .903 201 90 A 5,00 000 0H 30 .303 B 000 2.00 .988 .29a 388 38 c 5.00 400 :984 .31e .380382 D 500 1000-578 ,578 a ,570 Equation for A as f(mL std) k = Equation for A as f(mg Mn)K % Mn in steel sample 96 Mn Attach a neat Standard Additions Plot. Write the slope of the line, the y-intercept an the correlation coefficient for the line on the graph. (5%)Explanation / Answer
I think that if we write the beer law which is:
A = EbC
Where C is concentration and E molar absorptivity of the compound, which in this case, I think is k.
Now, if this is the case, then you will need to plot a curve of C vs A, the concentration of standard you may have it by doing this:
C = Cstd * (Vi/Vf)
The Vi is the innitial volume added to the solution and Vf is the final volume of solution, for example for measuerement two the final volume is 5+2 and the innitial is 2. With that you can calculate the concentration.
Once you have that, then plot C vs A. you will get a linear equation of the form: y = a + bx
Where a is the Ao, and b will be the value of k.
Once you have the value of k, substiute in the previous equation of the linear, the value of concentration of the sample to get the absorbance for the sample.
Finally the %Mn will be dividing the concentration of the previous standard plot by the concentration of the mass sample times 100.
Hope this helps. If you get stuck tell me in a comment.
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