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A buffer solution contains 0.479 M CH3NH3Cl and 0.313 M CH3NH2 (methylamine). De

ID: 994857 • Letter: A

Question

A buffer solution contains 0.479 M CH3NH3Cl and 0.313 M CH3NH2 (methylamine). Determine the pH change when 0.063 mol NaOH is added to 1.00 L of the buffer. pH after addition pH before addition = pH change =

A buffer solution contains0.337 M NaHCO3 and0.244 M K2CO3. Determine the pH changewhen 0.071 mol HNO3 is added to 1.00 L of the buffer.

pH change =


A buffer solution contains0.351 M NH4Br and0.300 M NH3 (ammonia). Determine the pH changewhen 0.068 mol HClO4 is added to 1.00 L of the buffer.

pH after addition pH before addition = pHchange =

Explanation / Answer

pH of buffer is calculated using Henderson Hasselbalch Equation

pH = pKa + log base/acid

Ka of methyl ammonium is 2.3 x 10-11

pKa = - log Ka

pKa = - log 2.3 x 10-11

pKa = 10.64

pH = pKa + log base/acid

pH = 10.64 + log 0.313/0.479

pH = 10.64 -0.185

pH = 10.45 before adding NaOH

When 0.063 mol of NaOH is added the base concentration becomes 0.376 M and the ammonium concentration reduces to 0.416 M.

So the new pH is

pH = pKa + log base/acid

pH = 10.64 + log 0.376/0.416

pH = 10.64 -0.044

pH = 10.60 after adding NaOH

pH change = 10.60 - 10.45 = 0.15

2) Bicarbonate pKa = 10.3

pH before adding HNO3 is

0.337 M NaHCO3 and0.244 M K2CO3

pH = pKa + log base/acid

pH = 10.3 + log 0.244/0.337

pH = 10.3 -0.14

pH = 10.16

After adding 0.071 mol HNO3

0.337 + 0.071 = 0.408M NaHCO3 and 0.244 - 0.071 = 0.173 M K2CO3

pH = pKa + log base/acid

pH = 10.3 + log 0.173/0.408

pH = 10.3 -0.372

pH = 9.93

pH Change = 10.16-9.93 = 0.23

3) pKa for ammonium = 9.24

pH before adding HClO4

0.351 M NH4Br and0.300 M NH3

pH = pKa + log base/acid

pH = 9.24 + log 0.3/0.351

pH = 9.24 -0.068

pH = 9.17

pH after adding 0.068 HClO4

0.351 + 0.068 = 0.419 M NH4Br and 0.300 -0.068 = 0.232 M NH3

pH = pKa + log base/acid

pH = 9.24 + log 0.232/0.419

pH = 9.24 -0.26

pH = 8.98

pH change = 9.17 - 8.98 = 0.19