Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Which correctly distinguishes a voltaic cell from an electrolytic cell? In the r

ID: 995107 • Letter: W

Question

Which correctly distinguishes a voltaic cell from an electrolytic cell? In the redox reaction 2MnO_4^-(aq) + l6H^+(aq) + 5Sn^2+(aq) rightarrow 2Mn^2+(aq) + 8H_20(I) + 5Sn^4+(aq) the oxidation number of manganese changes from to. +7, +2 +2, +4 -1, +4 -1, +2 Consider a galvanic cell based on the half reactions: Cu^2+ + 2e rightarrow Cu E^o = 0.34 V Cr^3+ + 3e^- rightarrow Cr E^o = -0.74 V What is the anode reaction? Cr^3+(aq) + 3e^- rightarrow Cr(s) Cu2+(aq) + 2e^- rightarrow Cu(s) Cr(s) rightarow Cr^3+(aq) + 3e^- Cu (s) rightarrow Cu^2+(aq) + 2e^- The purpose of a salt bridge in a galvanic cell is to correct any volume changes in the cell. maintain charge balance in the cell. provide ions to be oxidized and reduced. provide a path for the flow of free electrons. If an aqueous solution of sodium iodide is electrolyzed, what are the principal products found at

Explanation / Answer

56)

we know that


in both cases , reduction takes place at cathode , oxidation takes at anode

now


in voltaic cell , dG < 0

in electrolytic cell , dG > 0


in voltaic cell , anode is negative

in electrolytic cell , anode is positive

SO

A is the answer

57)

reactant : MnO4-

overall charge = - 1

so

oxidation number of Mn - ( 4 x-2) = - 1

oxidation number of Mn = -1 + 8 = + 7

products : Mn+2

so

the oxidation number changed from +7 to +2

the answer is A) +7,+2

58)

we know that

half reaction with lower reduction potential is anode

so

half reaction with chromium is anode

also

we know that

oxidation takes place at anode

so

the anode reaction is

Cr ---> Cr+3 + 3e-

so

answer is C) Cr(s) ---> Cr+2 (aq) + 3e-

59)

the answer is

B) maintian charge balance in the cell

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote