what mass of precipitate will form of excess Pb(ClO3)2 is mixed CHE 166-Spring16

Question

what mass of precipitate will form of excess Pb(ClO3)2 is mixed CHE 166-Spring16-MILLS Activities and Due Dates skills Practice Video F 5/7/2016 11:55 PM O 2.5/35/7/2016 08:03 PM Print HCaontor-Perode Table Grade Question 3 of 3 Map Ammonia, NHs, may react with oxygen to form nitrogen gas and water 2N2(g) +6H20 If 2.35 g of NHs reacts with 3.53 g O2 and produces 0.750 L of No, at 295 K and 1.00 atm, which reactant is limiting? What is the percent yield of the reaction? Number There is a hint availablel View the hint by clicking on the botiom divider bar divider bar again to hide the hint Close

Explanation / Answer

mol of NH3 = m/MW = 2.35/17 = 0.1382352

mol of O2 = m/MW = 3.53/32 = 0.11031

mol of N2 = from ideal gas

PV = nRT

n = PV/(RT) = 1*0.75/(0.082*295) = 0.03100

limit -->

O2 --> 4/3*0.11031 = 0.14708 mol of NH3 required which we do NOT have

so NH3 limits the reaction

0.1382352 mol of NH3 = 0.1382352*2/4 = 0.06911

Yield = real/theoretical = 0.03100/0.06911*100 = 44.8560 %

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.