Write the net ionic equation for the neutralization reaction of hydrochloric aci
ID: 996360 • Letter: W
Question
Write the net ionic equation for the neutralization reaction of hydrochloric acid and sodium hydroxide. Had you written complete ionic equation, what would the spectator have been? What is the pH of ao aqueous solution composed of 0.20 M NH_4^+ and 0.64 M NH_3? (k. of NH_4^+ = 5.6 times 10^minus16) Which of the following combinations would be best to buffer an aqueous solution at a pH of 7 .07 H_3PO_4 and H_2PO_4^minus, K_al = 7.5 times 10^minus3 HNO_2 and NO_2^minus, K_a = 4.5 times 10^minus3 CH_3Co_2H and CH_3 COO^minus, k_a = 1.8 times 10^minus3 H_2 PO_4^minus and HPO_4^2minus, K_a2 = 6.2 times 10^minus3 NH_4 and NH_3, K_a = 5.7 times 10^minus10 The K_a of bicarbonate ion, HCO_2^minus, is 4.8 times 106minus11. What [CO_3^2] [HCO_3^minus] ratio is necessary to make a buffer with a pH of 11.00? Write the solubility product expression for Cu(II) hydroxide. Cu(OH)_2. At what temperature is entropy = 0? Which of the following linear chain alcohols is likely to hate the highest standard entropy in the liquid state Explain why you chose this answer. CH_3OH CH_3CH_2OH CH_3CH_2CH_2OH CH_3CH_2CH_2CH_2OH CH_33CH_2CH_2CH_2CH_2OH Hydrogen gas is a non-polluting fuel. Hydrogen gas may be prepared by electrolysis of water 2 H_2O(l) rightarrow 2 H_2(g) + O_2(g) Predict the signs of deltasS for the production of hydrogen gas by electrolysis of waterExplanation / Answer
17)
The ionic equation will be
Na+ + OH- + H+ + Cl- --> H2O + Na+ + Cl-
The spectator ions are Na+ and Cl-
18) We will use Henersen Hassalbalch equation here
pOH = pKb + log [Salt] / [base]
Ka of NH4+ -= 5.6 X 10^-10
So Kb of NH3 = 10^-14 / 5.6 X 10^-10 = 1.78 X 10^-5
pKb = 4.75
Sp
pOH = 4.75 + log[0.2] / [0.64]
pOH = 4.24
pH = = 14 - pOH = 14 -4.24 = 9.76
19) The solution whose pKa is near to pH= 7
so answer is H3PO4- and H2PO4-2
20 ) AGain
pH = pKa + log [salt] / [acid]
salt = CO3-2
acid= HCO3-
Ka= 4.8 X 10^-11
pKa = -logKa = 10.32
pH = 11
11 = 10.32 + log [salt] / [acid]
log[salt]/ [acid] = 0.68
Taking antilog
[CO3-2] / [HCO3-] = 4.786
21) solubility product expression will be
Ksp = [Cu+2] [OH-]2
22) At zero kelvin the entropy is zero
23) The highest entropy will be of pentanol, as the size increases the complexity of molecule increases and hence the number of ways in which energy can be distributed increases
24) The enthalpy should be positive as heat will be required for splitting of water
And the entropy should be positive as the less random state is converting to more random state
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