The addition of solid Na_2S0_4 to an aqueous solution in equilibrium with solid

Question

The addition of solid Na_2S0_4 to an aqueous solution in equilibrium with solid BaSO_4 will cause. (Circle one) no change in [Ba^2+] in solution, more BaS04 to dissolve, precipitation of more BaSO4. an increase in the of BaS04. If two salts, AX and BX_2, have the same values of 4.0 x 10^-12 at a given temperature, then (Circle one) their molar solubilities in water are the same, the salts are more soluble in 0.1 M NaX than in water, the molar solubility of AX in water is less than that of BX2. addition of NaX will not affect the solubilities of the salts.

Explanation / Answer

(c) More of the BaSO4 to precipitate.

Consider the equilibrium

BaSO4(s) <==> Ba2+ + SO42-

Here it shows the “common ion effect". According to LeChatelier's principle adding Ba2+ or SO42- will shift the equilibrium to the left to reduce the concentrations of ions and make more insoluble BaSO4. The Ksp of the BaSO4 won't be affected by changes in the ion concentration

9. c) The molar solubility of AX in water is less than that of BX2.

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