The amount of alcohol in a drink is typically reported as percent alcohol by vol

Question

The amount of alcohol in a drink is typically reported as percent alcohol by volume. Volume percent or volume/volume percent (% v/v) most often is used when preparing solutions of liquids. Volume percent is defined as:
% v/v = Vsolute/Vsolution  × 100
Find the percent alcohol (ethanol) by volume for the vodka used in the lab by following the steps outlined in the table below.

(f) multiply the percent alcohol by volume in the diluted vodka solution by the dilution factor to obtain the % v/v alcohol in the original vodka solution.

Im having a lot of trouble filling out this last chart.

(a) given the molar mass of ethanol of 46.07 g/mol, calculate the mass of alcohol (ethanol) in the tested sample solution (2.0 mL were used with dilution to 1/50th or 2% of origional concentration.) Test sample was (b) given the density of ethanol of 0.7893g/ml, find the volume in mL of ethanol present in the diluted vodka solution (c) record the volume of vodka used in the experiment in mL (d) find the percent alcohol by volume (% v/v) in the diluted vodka solution (e) the diluted vodka solution was prepared by diluting 2.00 mL vodka to 100.00 mL. Calculate the dilution factor used (N:1)

(f) multiply the percent alcohol by volume in the diluted vodka solution by the dilution factor to obtain the % v/v alcohol in the original vodka solution.

Im having a lot of trouble filling out this last chart.

Explanation / Answer

a) molar mass of ethanol = 46.07 g / mole

We know that volume% of alcohol in vodka = 40%

So in 100mL, 40mL of ethanol is present

Volume used = 2mL

diluted = 1/50th

so volume of ethanol taken = 2/50 = 0.04 mL

b) the density = 0.7893

Mass of ethanol = 0.04 x 0.7893 = 0.03157 grams

c) % volume of diluted vodka can be calculated as

Initial = 40%

initial volume used= 2mL

Final volume = 2 X 50 = 100 mL

Final % = 40 X 2 / 100 = 0.8 % V / V

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