Which one of the following substances, will NOT display H- bonding? NH_3 HF H_2O

Question

Which one of the following substances, will NOT display H- bonding? NH_3 HF H_2O H_2S all substances can display H- bonding Which substance is expected to have the highest melting point? CO_2 CH_3OH CH4 D)CS_2 KCl Which of the following particles or rays requires barriers of lead ami or concrete for adequate protection? alpha beta gamma proton electron What volume of CO_2 gas at 645 torr and 800 K could be produced by the reaction of 45.0 g of CaCO_3 according to the equation? C_aCO_3CaO(s) +CO_2H_(g) 0.449 L B) 22.4 L C) 25.0 L D) 34.8 L E) 45.7 mL Consider 1.00 L of air in a patient's lungs at 37.0 degree C and 1.00 atm pressure. What volume would this air occupy if it were at 25 degreeC under a pressure of 5.00 times 10^2 atm (a typical pressure in a compressed air cylinder)? 1.35 times 10^-3 Calculate the volume occupied by 35.2 g of methane gas (CH_4) at 25.0degreeC and 1.00 atm. R 0.0821 L-atm/K-mol. A) 0.0186 L B) 4.50 L Q11.2L D)49.2L E) 53.7 L Which of these properties is. are charactcristic(s) of gases? High compressibility. Relatively large distances between molecules. Formation of homogeneous mixtures regardless of the nature of oases A and B. A. b and C.

Explanation / Answer

11)D) H2S is a gas ,its molecules are free from each other .No H-bonding as the difference of electronegativity of H and S is not large.Therefore less partial charges on H and S as S does not pull the bonding electrons between H and S much strongly. Electronegativity decreases down the group ,So S is less electronegative than O in the same group.

12)E)KCl ionic compunds have highest m.pt.K+ and Cl- have strong electrostatic attractions so it forms crystal having strong ionic bond

13)C) gamma rays are the most penetrating of all radiations

14)moles of CaCO3=mass/molar mass=45.0g/100.09 g/mol=0.45 moles=moles of CO2

using ideal gas equation,PV=nRT ,p=pressure,V=volume ,n=moles,R=universal gas constant,T=temperature

1torr=0.00131579 atm

645 torr=0.00131579 atm*645 =0.85 atm

V=nRT/P =0.45 moles*(0.0821 L atm/K mol) *800K/0.85 atm=34.8 L(D)

15)P * V/T=P' * V'/T'

P=1 atm

V=1L

T=37+273=310K

P'=500 atm

V'=?

T'=25+273=298K

V'=P * V*T'/T*P'

=1atm*1L*298K/310K*500atm=0.00192 L=1.92*10^-3 L

16)ideal gas equation gives,V=nRT/P

n=35.2g/16.04g/mol=2.19

V=2.19 mol*0.0821 L atm/K.mol *298K/1.00 atm=53.7 L

17)E

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