Which is a precipitation reaction? 2Cr + 6HNO_3 (aq) rightarrow 2Cr(NO_3)_3 (aq)

Question

Which is a precipitation reaction? 2Cr + 6HNO_3 (aq) rightarrow 2Cr(NO_3)_3 (aq) + 3H_2 H_3PO_4 (aq) + 3KOH(aq) rightarrow K_3PO_4 (aq) + 3H_2O 3Ba(NO_3)_2 (aq) + 2Na_3PO_4 (aq) rightarrow Ba_3(PO_4)_2 + 6NaNO_3 (aq) NaHCO_3 (aq) + HCl (aq) rightarrow NaCl (aq) + CO_2 + H_2O What is the net ionic equation for the reaction of aqueous solutions of Pb(NO_3)_2 and KCl? Pb^2+ (aq) + Cl^- (aq) rightarrow PbCl_2 Pb^2+ (aq) + 2Cl^- (aq) rightarrow PbCl_2 Pb(NO_3)_2 (aq) + 2KCl (aq) rightarrow 2KNO_3 (aq) + PbCl_2 2K^+ (aq) + 2Cl^- (aq) + Pb^2+ (aq) + 2NO^-_3 (aq) rightarrow 2K^+ (aq) + 2NO^-_3(aq) + PbCl_2 From these measurements, we can conclude any acid was added solutions 1 and 3 are buffers but greater buffer capacity than 1. solutions 2 and 4 are buffers but greater buffer capacity than 4. solutions 3 and 4 are buffers but greater buffer capacity than 3. none of the four initial solutions is a b Equal volumes of solutions of acids and the salts are mixed to prepare a buffer. The closest to 5.0 was prepared by mixing 1.0 times 10^-5 M hydrochloric acid and 0.1 0.10 M benzoic acid (K_a = 6.3 times 10^-5) sodium benzoate 0.10 M butyric acid (K_a = 1.5 times 10^-5) sodium butyrate 0.10 M formic acid (K_a = 4.3 times 10^-4) sodium formate

Explanation / Answer

Q 27) Option C -- BArium-Phosphate is getting precipitated out in solid form
In the rest of the options all the products areeither in gaseous form or aqueous form or liquid form
Q28) Option B
Steps to write Net ionic Reaction --
1) Write a balanced molecular reaction (Which is given in option C)
2) Dissociate all strong electrolytes (Which is done in option D)
3) Cross out the spectator ions ie the ions which do not change their Oxidation No. or state from left to right side of the reaction -- In our case only Pb and Cl do that.
Both of them are not changing Oxidation No. but are changing from aq to Solid form
4)Writing the net ionic eqn with the remaing ions gives us Option B as correct answer

Note -- Option A is incorrect because the reaction is not molecularly balanced

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